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Question
Find the value of x from the following figure.

Sum
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Solution
Given: Right-angled triangle with base (adjacent to 30°) = 30 m, right angle at left, angle at right = 30°. Let hypotenuse = x.
Step-wise calculation:
1. Use cosine for the 30° angle:
cos 30° = `"Adjacent"/"Hypotenuse"`
= `30/x`
`cos 30^circ = sqrt(3)/2`
2. So, `sqrt(3)/2 = 30/x`
3. Solve for x:
`x = 30 xx 2/sqrt(3)`
= `60/sqrt(3)`
= `(60sqrt(3))/3`
= `20sqrt(3)`
4. Decimal: `20sqrt(3)`
= 20 × 1.732
= 34.64 m
x = `20sqrt(3)` m ≈ 34.64 m.
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