Advertisements
Advertisements
Question
Find the value of the following:
sin 76° cos 16° – cos 76° sin 16°
Advertisements
Solution
Given that, sin 76° cos 16° – cos 76° sin 16° (∴ This is of the form sin(A – B))
= sin(76° – 16°)
= sin 60°
`= sqrt3/2`
APPEARS IN
RELATED QUESTIONS
Find the value of the following:
sin (-105°)
Find the value of the following:
cos 70° cos 10° – sin 70° sin 10°
If sin A = `12/13`, find sin 3A.
Prove that `(sin ("B - C"))/(cos "B" cos "C") + (sin ("C - A"))/(cos "C" cos "A") + (sin ("A - B"))/(cos "A" cos "B")` = 0
If tan A – tan B = x and cot B – cot A = y prove that cot(A – B) = `1/x + 1/y`.
If sin α + sin β = a and cos α + cos β = b, then prove that cos(α – β) = `(a^2 + b^2 - 2)/2`
If tan α = `1/7`, sin β = `1/sqrt10`. Prove that α + 2β = `pi/4` where 0 < α < `pi/2` and 0 < β < `pi/2`.
Show that `cos^-1 (12/13) + sin^-1 (3/5) = sin^-1 (56/65)`
The value of sin 28° cos 17° + cos 28° sin 17°
If p sec 50° = tan 50° then p is:
