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Find the value of the following expression: 2 sin^2 30° – 3 cos^2 45° + tan^2 60° - Mathematics

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Question

Find the value of the following expression:

2 sin2 30° – 3 cos2 45° + tan2 60°

Sum
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Solution

Given: 2 sin2 30° – 3 cos2 45° + tan2 60°

Step-wise calculation:

`sin 30^circ = 1/2`

⇒ `sin^2 30^circ = (1/2)^2`

= `1/4`

⇒ `2 xx (1/4) = 1/2`

`cos 45^circ = sqrt(2)/2`

⇒ `cos^2 45^circ = (sqrt(2)/2)^2`

= `1/2`

⇒ `-3 xx (1/2) = -3/2`

`tan 60^circ = sqrt(3)`

⇒ `tan^2 60^circ = (sqrt(3))^2`

= 3

Now sum: `1/2 - 3/2 + 3`

= `(1/2 - 3/2) + 3` 

= –1 + 3

= 2

The value of the expression is 2.

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Chapter 18: Trigonometric Ratios of Some Standard Angles and Complementary Angles - Exercise 18A [Page 372]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 18 Trigonometric Ratios of Some Standard Angles and Complementary Angles
Exercise 18A | Q 4. | Page 372
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