Advertisements
Advertisements
Question
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = `kx^2 - sqrt2x +1`
Advertisements
Solution
If x − 1 is a factor of polynomial p(x), then p(1) must be 0.
p(x) = `kx^2 - sqrt2x +1`
p(1) = 0
⇒ `k(1)^2 - sqrt2(1) + 1 = 0`
⇒ `k - sqrt2 + 1=0`
⇒ `k = sqrt2 - 1`
Therefore, the value of k is `sqrt2 -1`.
APPEARS IN
RELATED QUESTIONS
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = kx2 – 3x + k
Factorise:
2x2 + 7x + 3
Factorise:
x3 + 13x2 + 32x + 20
Factorise:
2y3 + y2 – 2y – 1
Find the factor of the polynomial given below.
`sqrt 3 x^2 + 4x + sqrt 3`
x + 1 is a factor of the polynomial ______.
One of the factors of (25x2 – 1) + (1 + 5x)2 is ______.
Factorise:
84 – 2r – 2r2
Factorise:
`2sqrt(2)a^3 + 8b^3 - 27c^3 + 18sqrt(2)abc`
Without finding the cubes, factorise:
(x – 2y)3 + (2y – 3z)3 + (3z – x)3
