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Question
Find the value of θ from the following:
cos (2θ – 50°) = sin 60°
Sum
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Solution
Given: cos (2θ – 50°) = sin 60°
Step-wise calculation:
1. Convert sin ⇒ cos using (sin x = cos (90° – x)):
sin 60° = cos (90° – 60°)
= cos 30°
So, the equation becomes cos (2θ – 50°) = cos 30°.
2. If cos A = cos B, then A = 360°k ± B, where k ∈ Z.
Hence, 2θ – 50° = 360°k + 30° or 2θ – 50° = 360°k – 30°.
3. Solve each case:
Case (i): 2θ – 50° = 360°k + 30°
2θ = 360°k + 80°
θ = 180°k + 40°
Case (ii): 2θ – 50° = 360°k – 30°
2θ = 360°k + 20°
θ = 180°k + 10°
θ = 180°k + 40° or θ = 180°k + 10°, k ∈ Z
If θ is restricted to (0° ≤ θ ≤ 180°), then (θ = 40°) or (θ = 10°).
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Chapter 18: Trigonometric Ratios of Some Standard Angles and Complementary Angles - Exercise 18A [Page 373]
