Question

Find the two-third life, t_2/3, of a first order reaction in which k = 5.4 × 10⁻¹⁴ s.

Answer 1

To find the two-third life (t_2/3) of a first-order reaction with rate constant k = 5.4 × 10⁻¹⁴ s⁻¹, use the formula derived from the integrated rate law:

`t_(2//3) = 1/k ln (1/(1 - 2/3))`

= `1/k ln (3)`

Given:

k = 5.4 × 10⁻¹⁴ s⁻¹

ln⁡(3) ≈ 1.0986

Now calculate

`t_(2//3) = 1.0986/(5.4 xx 10^-14)`

= 2.034 × 10¹³ seconds