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Question
Find the sequence that minimizes the total elapsed time required to complete the following task. The table below gives the processing time in hours. Also, find the minimum elapsed time and idle times for both machines.
| Jobs | 1 | 2 | 3 | 4 | 5 |
| M1 | 3 | 7 | 4 | 5 | 7 |
| M2 | 6 | 2 | 7 | 3 | 4 |
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Solution
Using optimal sequence algorithm, the following optimal sequence can be obtained.
| Jobs | 1 | 2 | 3 | 4 | 5 |
| M1 | 3 | 7 | 4 | 5 | 7 |
| M2 | 6 | 2 | 7 | 3 | 4 |
Here, min{ M1, M2 } = 2
Which corresponds to Job 2 of Machine 2.
∴ Job 2 is processed last
| 2 |
Now, the remaining Jobs are 1, 3, 4, and 5
Here, Min{ M1, M2 } = 3
Which corresponds to Job 1 of Machine 1 and Job 4 of machine 2.
∴ Job 1 is processed first and Job 4 is processed fourth before Job 2. i.e;
| 1 | 4 | 2 |
Again, the remaining Jobs are 3 and 4
Here, Min {M1, M2 } = 4
Which corresponds to Job 3 of machine 1 and Job 5 of machine 2.
∴ Job 3 is processed second after Job 1 and Job 5 is processed third before Job 4
i.e.
| 1 | 3 | 5 | 4 | 2 |
This is the optimal sequence for completing a table.
Now we find the total elapsed times as follows:
| Jobs | Machine M1 | Machine M2 | Idle time for M2 | ||
| Time in | Time out | Time in | Time out | ||
| 1 | 0 | 3 | 3 | 9 | 3 |
| 3 | 3 | 7 | 9 | 16 | 0 |
| 5 | 7 | 14 | 16 | 20 | 0 |
| 4 | 14 | 19 | 20 | 23 | 0 |
| 2 | 19 | 25 | 26 | 28 | 3 |
Total elaspsed time = 28 Hrs.
Idle time for M1 = 2 Hrs.
Idle time for M2 =6 Hrs.
