Advertisements
Advertisements
Question
Find the rank of the matrix
A = `((4, 5, 2, 2),(3, 2, 1, 6),(4, 4, 8, 0))`
Advertisements
Solution
A = `[(4, 5, 2, 2),(3, 2, 1, 6),(4, 4, 8, 0)]`
The order of A is 3 × 4
∴ p(A) < 3
Let us transform the matrix A to an echelon form
| Martix | Elementary Transformation |
| A = `[(4, 5, 2, 2),(3, 2, 1, 6),(4, 4, 8, 0)]` | |
| `∼ [(3, 2, 1, 6),(4, 5, 2, 2),(4, 4, 8, 0)]` | `{:"R"_1 ↔ "R"_2:}` |
| `∼ [(3, 2, 1, 6),(4, 5, 2, 2),(0, -1, 6, -2)]` | `{:"R"_3 ↔ "R"_2:}` |
| `∼ [(3, 2, 1, 6),(1, 3, 1, -4),(0, -1, 6, -2)]` | `{:"R"_2 -> "R"_2 - "R"_1:}` |
| `∼ [(1, 3, 1, -4),(3, 2, 1, 6),(0, -1, 6, -2)]` | `{:"R"_1 ↔ "R"_2:}` |
| `∼ [(1, 3, 1, -4),(0, -7, -2, 18),(0, -1, 6, -2)]` | `{:"R"_2 -> "R"_3 - 3"R"_1:}` |
| `∼ [(1, 3, 1, -4),(0, -1, 6, -2),(0, -7, -2, 18)]` | `{:"R"_2 ↔ "R"_3:}` |
| `∼ [(1, 3, 1, -4),(0, -1, 6, -2),(0, 0, -44, 32)]` | `{:"R"_3 -> "R"_3 - 3"R"_1:}` |
The last equivalent matrix is in the echelon form.
Number of non-zero rows = 3
∴ p(A) = 3
APPEARS IN
RELATED QUESTIONS
Show that the equations 5x + 3y + 7z = 4, 3x + 26y + 2z = 9, 7x + 2y + 10z = 5 are consistent and solve them by rank method
Choose the correct alternative:
A = (1, 2, 3), then the rank of AAT is
Choose the correct alternative:
The rank of m n × matrix whose elements are unity is
Choose the correct alternative:
If p(A) = r then which of the following is correct?
Choose the correct alternative:
The rank of the diagonal matrix `[(1, , , , ,),(, 2, , , ,),(, , -3, , ,),(, , , 0, ,),(, , , , 0,),(, , , , ,0)]`
Choose the correct alternative:
For the system of equations x + 2y + 3z = 1, 2x + y + 3z = 3, 5x + 5y + 9z = 4
Choose the correct alternative:
The system of linear equations x = y + z = 2, 2x + y – z = 3, 3x + 2y + k = 4 has unique solution, if k is not equal to
Find k if the equations 2x + 3y – z = 5, 3x – y + 4z = 2, x + 7y – 6z = k are consistent
Find k if the equations x + y + z = 1, 3x – y – z = 4, x + 5y + 5z = k are inconsistent
Let S be the set of all λ ∈ R for which the system of linear equations
2x – y + 2z = 2
x – 2y + λz = –4
x + λy + z = 4
has no solution. Then the set S ______.
