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Find the number of different ways of arranging letters in the word PLATOON if the two O’s are never together - Mathematics and Statistics

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Question

Find the number of different ways of arranging letters in the word PLATOON if the two O’s are never together

Sum
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Solution

When the two O’s are never together

Let us arrange the other 5 letters first, which can be done in 5! = 120 ways.

The letters P, L, A, T, N create 6 gaps, in which O’s are arranged.

Two O’s can take their places in 6P2 ways.

But ‘O’ repeats 2 times.

∴ Two O’s can be arranged in `(""^6"P"_2)/(2!)`

= `((6!)/((6 - 2)!))/(2!)`

= `(6 xx 5 xx 4!)/(4! xx 2 xx 1)`

= 3 × 5

= 15 ways

∴ Total number of arrangements if the two O’s are never together = 120 × 15 = 1800

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Chapter 3: Permutations and Combination - Exercise 3.4 [Page 57]

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Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
Chapter 3 Permutations and Combination
Exercise 3.4 | Q 15. (a) | Page 57
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