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Find the number of 6-digit numbers using the digits 3, 4, 5, 6, 7, 8 without repetition. How many of these numbers are not divisible by 5? - Mathematics and Statistics

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Question

Find the number of 6-digit numbers using the digits 3, 4, 5, 6, 7, 8 without repetition. How many of these numbers are not divisible by 5?

Sum
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Solution

A number of 6 different digits is to be formed from the digits 3, 4, 5, 6, 7, 8 which can be done in 6P6
i.e., 6! = 720 ways
If the number is not divisible by 5, then
Unit’s place can be any digit from 3, 4, 6, 7, 8 which can be selected in 5 ways.
Other 5 digits can be arranged in 5P5 i.e., 5! ways
∴ Total number of ways in which numbers not divisible by 5 can be formed = 5 × 5! = 5 × 120 = 600

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Permutations - Permutations When Repetitions Are Allowed
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Chapter 6: Permutations and Combinations - Exercise 6.3 [Page 81]

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Balbharati Mathematics and Statistics 2 (Commerce) [English] 11 Standard Maharashtra State Board
Chapter 6 Permutations and Combinations
Exercise 6.3 | Q 12. (ii) | Page 81

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