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Question
Find the median and mode:
| xi | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| fi | 1 | 2 | 3 | 3 | 6 | 10 | 5 | 4 | 3 | 3 |
Sum
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Solution
To find the median and mode for the data provided in the table, we first need to organize the values and calculate the cumulative frequency.
Frequency distribution table
| Value (xi) |
Frequency (fi) |
Cumulative Frequency (cf) |
fi × xi |
| 1 | 1 | 1 | 1 |
| 2 | 2 | 3 | 4 |
| 3 | 3 | 6 | 9 |
| 4 | 3 | 9 | 12 |
| 5 | 6 | 15 | 30 |
| 6 | 10 | 25 | 60 |
| 7 | 5 | 30 | 35 |
| 8 | 4 | 34 | 32 |
| 9 | 3 | 37 | 27 |
| 10 | 3 | 40 | 30 |
| Total | N = 40 | Σfixi = 240 |
1. Finding the mode
The mode is the value that appears most frequently in the data set.
Looking at the frequency (fi) column, the highest frequency is 10.
This frequency corresponds to the value xi = 6.
Mode = 6
2. Finding the median
Since the total frequency N is 40 an even number, the median is the average of the `(N/2)^(th)` and `(N/2 + 1)^(th)` observations.
1. Calculate positions: `40/2` = 20th and 20 + 1 = 21st positions.
2. Locate these in the cumulative frequency (cf):
- The 15th observation is 5.
- Observations from the 16th to the 25th are all 6.
3. Both the 20th and 21st observations are 6.
Median = 6
3. Finding the mean
The second part of your image asks for the mean.
We can calculate this using the formula `barx = (sumf_ix_i)/N`:
`barx = 240/40`
`barx = 6`
Mean = 6
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