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Question
Find the mean and the mode for the following data:
| Class | Frequency |
| 5 – 10 | 5 |
| 10 – 15 | 6 |
| 15 – 20 | 15 |
| 20 – 25 | 10 |
| 25 – 30 | 5 |
| 30 – 35 | 4 |
| 35 – 40 | 2 |
| 40 – 45 | 2 |
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Solution
1. Calculation of mean
To find the mean `(barx)` for grouped data, we use the formula:
`barx = (sumf_ix_i)/(sumf_i)`
where fi is the frequency and xi is the class mark (mid-point) of each class.
| Class | Frequency (fi) | Class Mark (xi) | fixi |
| 5 – 10 | 5 | 7.5 | 37.5 |
| 10 – 15 | 6 | 12.5 | 75.0 |
| 15 – 20 | 15 | 17.5 | 262.5 |
| 20 – 25 | 10 | 22.5 | 225.0 |
| 25 – 30 | 5 | 27.5 | 137.5 |
| 30 – 35 | 4 | 32.5 | 130.0 |
| 35 – 40 | 2 | 37.5 | 75.0 |
| 40 – 45 | 2 | 42.5 | 85.0 |
| Total | Σfi = 49 | Σfixi = 1027.5 |
Mean = `1027.5/49`
= 20.969
= 20.97
2. Calculation of mode
The modal class is the interval with the highest frequency, which is 15 – 20 (frequency = 15).
The formula for the mode is:
Mode = `L + ((f_1 - f_0)/(2f_1 - f_0 - f_2))xx h`
L = 15 ...(Lower limit of modal class)
f1 = 15 ...(Frequency of modal class)
f0 = 6 ...(Frequency of preceding class)
f2 = 10 ...(Frequency of succeeding class)
h = 5 ...(Class width)
Mode = `l + ((f_1 - f_0)/(2f_1 - f_0 - f_2)) xx h`
= `15 + ((15 - 6)/(2(15) - 6 - 10)) xx 5`
= `15 + (9/(30 - 16)) xx 5`
= `15 + (19/14) xx 5`
= `15 + 45/14`
= 15 + 3.214
= 18.21
