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Find the maximum profit that a company can make, if the profit function is given by p(x) = 41 − 72x − 18x2. - Mathematics

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Question

Find the maximum profit that a company can make, if the profit function is given by p(x) = 41 − 72x − 18x2.

Sum
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Solution

We have p(x) = 41 − 72x − 18x2

p'(x) = −72 − 36x

Now for critical points, p’(x) = 0

−72 − 36x = 0

−72 = 36x

x = `36/(−72)`

x = −2

p”(x) = −36 < 0

∴ Profit is maximum at x = −2, and maximum profit is p(−2) = 41 − 72 (−2) − 18 (−2)2

= 41 + 144 − 72

= 185 − 72

= 113

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Chapter 6: Application of Derivatives - Exercise 6.5 [Page 232]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 6 Application of Derivatives
Exercise 6.5 | Q 6 | Page 232

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