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Question
Find the mass of KNO3 required to produce 126 kg of nitric acid. Find whether a larger or smaller mass of NaNO3 is required for the same purpose.
\[\ce{KNO3 + H2SO4 -> KHSO4 + HNO3}\]
\[\ce{NaNO3 + H2SO4 -> NaHSO4 + HNO3}\]
Numerical
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Solution
The molecular mass of KNO3 = 101 g
63 g of HNO3 is formed by = 101 g of KNO3
So, 126 Kg of HNO3 is formed by = `(126 xx 101)/63` = 202 kg
Now, The molecular mass of NaNO3 = 85 Kg
126 g of HNO3 is formed by `(85 xx 126)/63` = 170 kg of NaNO3
So, a smaller mass of NaNO3 is required.
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