Advertisements
Advertisements
Question
Find the length of AD.
Given: ∠ABC = 60o.
∠DBC = 45o
and BC = 40 cm.
Advertisements
Solution
From right triangle ABC,
tan 60° = `"AC"/"BC"`
⇒ `sqrt(3) = "AC"/40`
⇒ AC = `40sqrt(3)"cm"`
From right triangle BDC,
tan 45° = `"DC"/"BC"`
⇒ 1 = `"DC"/(40)`
⇒ DC = 40 cm
From the figure, it is clear that AD = AC - DC
⇒ AD = `40sqrt(3) - 40`
⇒ AD = `40(sqrt3 - 1)`
⇒ AD = 29.28 cm
APPEARS IN
RELATED QUESTIONS
Find 'x', if:
Find angle 'A' if :
Find AD, if:
In trapezium ABCD, as shown, AB // DC, AD = DC = BC = 20 cm and A = 60°. Find: distance between AB and DC.
Use the information given to find the length of AB.
Find the length of AB.
In right-angled triangle ABC; ∠ B = 90°. Find the magnitude of angle A, if: AB is √3 times of BC.
A ladder is placed against a vertical tower. If the ladder makes an angle of 30° with the ground and reaches upto a height of 15 m of the tower; find length of the ladder.
Find AB and BC, if:
Find PQ, if AB = 150 m, ∠ P = 30° and ∠ Q = 45°.
