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Question
Find the integrals of the following:
`1/(4 - x^2)`
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Solution
`int 1/(4 - x^2) "d"x = int 1/((2)^2 - (x)^2) "d"x`
`int 1/("a"^2 - x^2) "d"x = 1/(2"a") log|("a" + x)/("a" - x)| + "c"`
`int 1/(4 - x^2) "d"x = 1/(2(2)) log |(2 + x)/(2 - x)| + "c"`
= `1/4 log |(2 + x)/(2 - x)| + "c"`
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