Question

Find the equation of the line containing point A(3, 5) and having slope `2/3`.

Answer 1

Given, slope(m) = `2/3` and the line passes through (3, 5).

Equation of the line in slope point form is y – y₁ = m(x – x₁)

∴ The equation of the required line is

y – 5 = `2/3("x" - 3)`

∴ 3(y – 5) = 2(x – 3)

∴ 3y – 15 = 2x – 6

∴ 2x – 3y + 9 = 0