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Find the eccentricity of the hyperbola 9y2 – 4x2 = 36. - Mathematics

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Question

Find the eccentricity of the hyperbola 9y2 – 4x2 = 36.

Sum
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Solution

Given equation is  9y2 – 4x2 = 36

⇒ `y^2/4 - x^2/9` = 1

Clearly it is a vertical hyperbola.

Where a = 3 and b = 2

We know that b2 = a2(e2 – 1)

⇒ 4 = 9(e2 – 1)

⇒ e2 – 1 = `4/9`

⇒ e2 = `1 + 4/9 = 13/9`

∴ e = `sqrt(13)/3`

Hence, the required value of e is `sqrt(13)/3`.

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Chapter 11: Conic Sections - Exercise [Page 203]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 11 Conic Sections
Exercise | Q 21 | Page 203

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