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Question
Find the derivative of the function y = f(x) using the derivative of the inverse function x = f–1(y) in the following: y = e2x-3
Sum
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Solution
y = e2x-3 ...(1)
We have to find the inverse function of y = f(x), i.e x in terms of y.
From (1),
2x – 3= log y
∴ 2x = log y + 3
∴ x = f–1(y)
= `(1)/(2)(log y + 3)`
∴ `"dx"/"dy" = (1)/(2)"d"/"dy"(logy + 3)`
= `(1)/(2)(1/y + 0)`
= `(1)/(2y)`
= `(1)/(2e^(2x - 3)` ...[By (1)]
∴ `"dy"/"dx" = (1)/(("dx"/"dy")`
= `(1)/(((1)/(2e^(2x - 3)))`
= 2e2x–3.
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