Question

Find the coordinates of point P where P is the midpoint of a line segment AB with A(–4, 2) and B(6, 2).

Solution :

Suppose, (–4, 2) = (x₁, y₁) and (6, 2) = (x₂, y₂) and co-ordinates of P are (x, y).

∴ According to the midpoint theorem,

x = `(x_1 + x_2)/2 = (square + 6)/2 = square/2 = square`

y = `(y_1 + y_2)/2 = (2 + square)/2 = 4/2 = square`

∴  Co-ordinates of midpoint P are `square`.

Answer 1

Suppose, (–4, 2) = (x₁, y₁) and (6, 2) = (x₂, y₂) and coordinates of P are (x, y).

∴ According to the midpoint theorem,

x = `(x_1 + x_2)/2 = (bb(-4) + 6)/2 = bb2/2` = 1

y = `(y_1 + y_2)/2 = (2 + bb2)/2 = 4/2` = 2

∴  The coordinates of midpoint P are (1, 2).