Question

Find the solution of the quadratic equation `3sqrt3x^2+10x+sqrt3=0`

Answer 1

The given quadratic equation is `3sqrt3x^2+10x+sqrt3=0` 

` 3sqrt3^2+10x+sqrt3=0` 

⇒`3sqrt3x^2+9x+x+sqrt3=0` 

⇒` 3sqrt3x(x+sqrt3)+1(x+sqrt3)=0` 

⇒`(x+sqrt3)(3sqrt3x+1)=0` 

⇒` x+sqrt3=0  or  3sqrt3x+1=0` 

⇒x=`-sqrt3  or  x=-1/(3sqrt3)=-sqrt3/9` 

Hence, `-sqrt3  and -sqrt3/9`  are the solution of the given equation.