Question

Find the roots of the quadratic equations `4x^2+4sqrt3x + 3 = 0` by applying the quadratic formula.

Answer 1

`4x^2 + 4sqrt3x + 3 = 0`

On comparing this equation with ax² + bx + c = 0, we get

a = 4, b = ` 4sqrt3` and c = 3

By using quadratic formula, we get

`x = (-b±sqrtb2 - 4ac)/(2a)`

`⇒ x = (-4sqrt3±sqrt48-48)/8`

`⇒ x = (-4sqrt3±0)/8`

`∴ x = (-sqrt3)/2 `