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Question
Find the ratio of the linear momenta of two particles of masses 1.0 kg and 4.0 kg if their kinetic energies are equal.
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Solution
Let the masses of the two particles be m1 and m2.
Given:
m1 = 1 kg
m2 = 4 kg
Now,
Kinetic energy of the first particle = Kinetic energy of the second particle
\[\left( \frac{1}{2} \right) m_1 v_1^2 = \left( \frac{1}{2} \right) m_2 v_2^2 \]
\[ \Rightarrow \frac{m_1}{m_2} = \frac{v_2^2}{v_1^2}\]
\[ \Rightarrow \frac{v_2}{v_1} = \sqrt{\frac{m_1}{m_2}}\]
\[ \Rightarrow \frac{v_1}{v_2} = \sqrt{\frac{m_2}{m_1}}\]
\[\text{ The ratio of linear momenta (mv) of the two particles,} \]
\[\frac{P_1}{P_2} = \frac{m_1 v_1}{m_2 v_2} = \frac{m_1}{m_2}\sqrt{\frac{m_2}{m_1}}\]
\[ = \sqrt{\frac{m_1}{m_2}} = \sqrt{\frac{1}{4}} = \frac{1}{2}\]
\[ \Rightarrow P_1 : P_2 = 1: 2\]
Therefore, the ratio of linear momenta is 1:2.
