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Question
Find mean and mode of the following distribution:
| Class | Frequency |
| 0-10 | 3 |
| 10-20 | 6 |
| 20-30 | 11 |
| 30-40 | 10 |
| 40-50 | 13 |
| 50-60 | 3 |
| 60-70 | 4 |
Sum
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Solution
| Class | Frequency (fi) | Class mark (xi) | fixi |
| 0-10 | 3 | 5 | 15 |
| 10-20 | 6 | 15 | 90 |
| 20-30 | 11 | 25 | 275 |
| 30-40 | 10 | 35 | 350 |
| 40-50 | 13 | 45 | 585 |
| 50-60 | 3 | 55 | 165 |
| 60-70 | 4 | 65 | 260 |
| Total | `sum f_i = 50` | `sum f_i x_i = 1740` |
`sum f_i = 3 + 6 + 11 + 10 + 13 + 3 + 4`
= 50
`sum f_ix_i = 15 + 90 + 275 + 350 + 585 + 165 + 260`
= 1740
Mean = `(sum f_ix_i)/(sum f_i)`
= `1740/50`
= 34.8
Highest frequency (h) = 10
Modal class = 40-50
∴ l = 40, h = 10, f1 = 13, f0 = 10 and f2 = 3
Mode = `l + (f_1 - f_0)/(2f_1 - f_0 - f_2) xx h`
= `40 + (13 - 10)/(2(13) - 10 - 3) xx 10`
= `40 + (13 - 10)/(26 - 13) xx 10`
= `40 + (3)/(13) xx 10`
= `40 + 30/13`
= 40 + 2.31
= 42.31
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