Question

Find the length of a chord which is at a distance of 4 cm from the centre of the circle of radius 6 cm.

Answer 1

Radius of circle (OA)= 6cm

Distant (OC)=4cm

In Δ OCA  by Pythagoras theorem

`AC^2+OC^2=OA^2`

⇒`AC^2+4^2=6^2`

⇒`AC^2=36-16`

⇒`AC=sqrt20 =4.47 cm`

WKT, the perpendicular distance from center to chord bisects the chord.

`AC=BC=4.47cm `

`Then ,  AB = 4.47+4.47`

`8.94  cm `