Advertisements
Advertisements
Question
Find k, if f(k) = 2k – 1 and fof(k) = 5
Advertisements
Solution
f(k) = 2k – 1
fof(k) = 5
f(f(k))m = f(2k – 1) = 5
⇒ 2(2k – 1) – 1 = 5
4k – 2 – 1 = 5
⇒ 4k = 8
k = 2
APPEARS IN
RELATED QUESTIONS
Find the value of k, such that fog = gof
f(x) = 2x – k, g(x) = 4x + 5
If f(x) = 2x – 1, g(x) = `(x + 1)/(2)`, show that fog = gof = x
If f : R → R and g : R → R are defined by f(x) = x5 and g(x) = x4 then check if f, g are one-one and fog is one-one?
Multiple choice question :
If f(x) = 2x2 and g(x) = `1/(3x)`, then fog is
Multiple choice question :
If g = {(1, 1), (2, 3), (3, 5), (4, 7)} is a function given by g(x) = αx + β then the value of α and β are
Given f(x) = log `((1 + x)/(1 − x))` and g(x) = `(3x + x^3)/(1 + 3x^2)`, then fog(x) equals ______.
Which statement correctly describes the order of applying functions in \(g\circ f\)?
If f: A→B and IA is the identity function on A, which relation is correct?
Which additional identity-function relation is valid whenever the composition is defined?
For \(f(x)=\frac{x-1}{x+1}\), what is the domain of \(f\circ f\)?
