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Question
Find k, if f(k) = 2k – 1 and fof(k) = 5
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Solution
f(k) = 2k – 1
fof(k) = 5
f(f(k))m = f(2k – 1) = 5
⇒ 2(2k – 1) – 1 = 5
4k – 2 – 1 = 5
⇒ 4k = 8
k = 2
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