Advertisements
Advertisements
Question
Find each of the following product: \[( - 7xy) \times \left( \frac{1}{4} x^2 yz \right)\]
Advertisements
Solution
To multiply algebraic expressions, we use commutative and associative laws along with the law of indices, i.e., \[a^m \times a^n = a^{m + n}\]
We have:
\[\left( - 7xy \right) \times \left( \frac{1}{4} x^2 yz \right)\]
\[ = \left( - 7 \times \frac{1}{4} \right) \times \left( x \times x^2 \right) \times \left( y \times y \right) \times z\]
\[ = \left( - 7 \times \frac{1}{4} \right) \times \left( x^{1 + 2} \right) \times \left( y^{1 + 1} \right) \times z\]
\[ = - \frac{7}{4} x^3 y^2 z\]
Thus, the answer is \[- \frac{7}{4} x^3 y^2 z\].
APPEARS IN
RELATED QUESTIONS
Find each of the following product:
(7ab) × (−5ab2c) × (6abc2)
Find the value of (5x6) × (−1.5x2y3) × (−12xy2) when x = 1, y = 0.5.
Evaluate each of the following when x = 2, y = −1.
\[(2xy) \times \left( \frac{x^2 y}{4} \right) \times \left( x^2 \right) \times \left( y^2 \right)\]
Simplify: 2x2(x3 − x) − 3x(x4 + 2x) − 2(x4 − 3x2)
Find the following product and verify the result for x = − 1, y = − 2:
(3x − 5y) (x + y)
Simplify:
(x2 − 2y2) (x + 4y) x2y2
Simplify:
(x3 − 2x2 + 5x − 7)(2x − 3)
Simplify:
(5x − 3)(x + 2) − (2x + 5)(4x − 3)
Simplify : (x − y)(x + y) (x2 + y2)(x4 + y2)
Simplify : (2.5p − 1.5q)2 − (1.5p − 2.5q)2
