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Question
Find the cube of \[- \frac{8}{11}\] .
Sum
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Solution
\[\because\] \[\left( - \frac{m}{n} \right)^3 = - \frac{m^3}{n^3}\]
\[\therefore\] \[\left( - \frac{8}{11} \right)^3 = - \left( \frac{8}{11} \right)^3 = - $\left( \frac{8^3}{{11}^3} \right)$ = - $\left( \frac{8 \times 8 \times 8}{11 \times 11 \times 11} \right)$ = - \frac{512}{1331}\]
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