English

Find correlation coefficient from the following data. Given:[Given:3=1.732] x 3 6 2 9 5 y 4 5 8 6 7 - Mathematics and Statistics

Advertisements
Advertisements

Question

Find correlation coefficient from the following data. `["Given:" sqrt(3) = 1.732]`

x 3 6 2 9 5
y 4 5 8 6 7
Sum
Advertisements

Solution

 xi yi xi2 yi2 xiyi
3 4 9 16 12
6 5 36 25 30
2 8 4 64 16
9 6 81 36 54
5 7 25 49 35
25 30 155 190 147

From the table, we have

n = 5, `sum"x"_"i"` = 25, `sum"y"_"i"` = 30, `sum"x"_"i"^2` = 155, `sum"y"_"i"^2` = 190, `sum"x"_"i""y"_"i"` = 147

`bar"x"=(sum"x"_"i")/"n"`

= `25/5`

= 5

`bar"y"=(sum"y"_"i")/"n"`

= `30/5`

= 6

Since, Cov (x, y) = `1/"n"sum"x"_"i""y"_"i"-bar"x"bar"y"`

∴ Cov (x, y) = `1/5xx147-(5xx6)`

= 29.4 − 30

 = − 0.6

`sigma_"x"^2=(sum"x"_"i"^2)/"n"-(bar"x")^2`

= `155/5-(5)^2`

 = 31 − 25

∴ `sigma_"x"^2` = 6

∴ σx = `sqrt6`

`sigma_"y"^2=(sum"y"_"i"^2)/"n"-(bar"y")^2`

= `190/5-(6)^2`

= 38 − 36

∴ `sigma_"y"^2` = 2

∴ σy = `sqrt2`

∴ σxσy = `sqrt6sqrt2=sqrt12`

= `2sqrt3`

= 2(1.732) = 3.464

Thus, the correlation coefficient between x and y is

r = `("Cov"("x,y"))/(sigma_"x"sigma_"y")`

= `(-0.6)/3.464`

= − 0.1732

shaalaa.com
Concept of Correlation Coefficient
  Is there an error in this question or solution?
Chapter 5: Correlation - Exercise 5.1 [Page 63]

RELATED QUESTIONS

Find correlation coefficient between x and y series for the following data.
n = 15, `bar"x"` = 25, `bar"y"` = 18, σx = 3.01, σy = 3.03, `sum("x"_"i" - bar"x") ("y"_"i" - bar"y")` = 122


The correlation coefficient between two variables x and y are 0.48. The covariance is 36 and the variance of x is 16. Find the standard deviation of y.


In the following data one of the value y of is missing. Arithmetic means of x and y series are 6 and 8 respectively. `(sqrt(2) = 1.4142)`

x 6 2 10 4 8
y 9 11 ? 8 7

Calculate the correlation coefficient


Correlation coefficient between x and y is 0.3 and their covariance is 12. The variance of x is 9, Find the standard deviation of y.


Two series of x and y with 50 items each have standard deviations of 4.8 and 3.5 respectively. If the sum of products of deviations of x and y series from respective arithmetic means is 420, then find the correlation coefficient between x and y.


Find the number of pairs of observations from the following data,
r = 0.15, `sigma_"y"` = 4, `sum("x"_"i" - bar"x")("y"_"i" - bar"y")` = 12, `sum("x"_"i" - bar"x")^2` = 40.


Given the following information, `sum"x"_"i"^2` = 90, `sum"x"_"i""y"_"i"` = 60, r = 0.8, `sigma_"y"` = 2.5, where xi and yi are the deviations from their respective means, find the number of items.


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between 2x and y


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between `"x"/2` and y


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between x and 3y


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between x – 5 and y – 3


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between x + 7 and y + 9


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between `("x" - 5)/7` and `("y" - 3)/8`?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×