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Question
Fill in the blank.
If y = y = [log (x)]2 then `("d"^2"y")/"dx"^2 =` _____.
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Sum
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Solution
If y = y = [log (x)]2 then `("d"^2"y")/"dx"^2 =(2(1 − log x))/x^2 `.
Explanation:
y = (log x)2
On differentiating w.r.t. x, we get,
`dy/dx = 2 log x d/dx (log x)`
`dy/dx = 2 log x. 1/x`
`dy/dx = (2log x)/x`
Again differentiating w.r to x, we get,
`(d^2y)/(dx^2) = 2 d/dx ((log x)/x)`
`(d^2y)/(dx^2) = 2 ((x d/dx (log x) − log x d/dx x)/x^2)`
`(d^2y)/(dx^2) = 2 ((x × 1/x − log x × 1)/x^2)`
`(d^2y)/(dx^2) = (2(1 − log x))/x^2`
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