Advertisements
Advertisements
Question
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x3 + 2abx2 + b2x
Advertisements
Solution
We have,
a2x3 + 2abx2 + b2x
= x(a2x2 + 2abx + b2)
= x[(ax)2 + 2 × ax × b + b2]
= x(ax + b)2
= x(ax + b)(ax + b)
APPEARS IN
RELATED QUESTIONS
Using a2 − b2 = (a + b) (a − b), find 12.12 − 7.92
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 5.1 × 5.2
Expand `("a"/2+"b"/3)^2`
Expand `("x"+1/2)^2`
`(("a" + "b")("a"^3 - "b"^3))/(("a"^2 - "b"^2))` = ___________
Simplify: (a + b)2 – 4ab
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x2 + 4x + 1
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
`9x^2 + 2xy + y^2/9`
If p + q = 12 and pq = 22, then find p2 + q2.
Find the length of the side of the given square if area of the square is 625 square units and then find the value of x.
