Advertisements
Advertisements
Question
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x3 + 2abx2 + b2x
Advertisements
Solution
We have,
a2x3 + 2abx2 + b2x
= x(a2x2 + 2abx + b2)
= x[(ax)2 + 2 × ax × b + b2]
= x(ax + b)2
= x(ax + b)(ax + b)
APPEARS IN
RELATED QUESTIONS
Find the following squares by suing the identities.
(b − 7)2
Simplify (a2 − b2)2
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 5.1 × 5.2
Use a formula to multiply of (2t – 5)(2t + 5)
Evaluate the following, using suitable identity
512
If a + b = 5 and a2 + b2 = 13, then ab = ?
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 14x + 49
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
16x2 + 40x + 25
The area of a rectangle is x2 + 7x + 12. If its breadth is (x + 3), then find its length.
Take suitable number of cards given in the adjoining diagram [G(x × x) representing x2, R(x × 1) representing x and Y(1 × 1) representing 1] to factorise the following expressions, by arranging the cards in the form of rectangles:
- 2x2 + 6x + 4
- x2 + 4x + 4.
Factorise 2x2 + 6x + 4 by using the figure.

Calculate the area of figure.
