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Factorise: a6 – 15625b6 - Mathematics

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Question

Factorise:

a6 – 15625b6

Sum
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Solution

Given expression is a6 – 15625b6

Applying the identity, we get,

⇒ (a3)2 – [(5b)3]2 = (a3 + [5b)3] [a3 – (5b)3]

We have

⇒ [a3 + (5b)3] = (a + 5b) [a2 – 5ab + (5b)2]

And

⇒ [a3 – (5b)3] = (a – 5b) [a2 + 5ab + (5b)2]

By grouping all these terms, we get,

⇒ (a + 5b) (a – 5b) (a2 – 5ab + 25b2) (a2 + 5ab + 25b2)

⇒ (a + 5b) (a – 5b) (a4 + 5a3b + 25a2b2 – 5a3b – 25a2b2 – 125ab3 + 25a2b2 + 125ab3 + 625b4

⇒ (a + 5b) (a – 5b) (a4 + 625b4 + 25a2b2)

Hence, factors for the expression a6 – 15625b6 is (a + 5b) (a – 5b) (a4 + 625b4 + 25a2b2)

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Chapter 4: Factorisation - MISCELLANEOUS EXERCISE [Page 48]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 4 Factorisation
MISCELLANEOUS EXERCISE | Q III. 3. | Page 48
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