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Factorise: 27a2b – 75b3 - Mathematics

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Question

Factorise:

27a2b – 75b3

Sum
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Solution

We are given the expression:

27a2b – 75b3

Step 1: Factor out the common factor:

The common factor in both terms is b, so we can factor out b:

27a2b – 75b3 = b(27a2 – 75b2)

Step 2: Factor further:

Now, we can factor 27a2 – 75b2.

Notice that both terms have a common factor of 3:

27a2 – 75b2 = 3(9a2 – 25b2)

Step 3: Recognise the difference of squares:

The expression 9a2 – 25b2 is a difference of squares, which can be factored as:

9a2 – 25b2 = (3a – 5b) (3a + 5b)

Final factorisation

So the fully factorised form is 3b(3a – 5b) (3a + 5b)

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Chapter 4: Factorisation - MISCELLANEOUS EXERCISE [Page 48]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 4 Factorisation
MISCELLANEOUS EXERCISE | Q I. 4. | Page 48
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