Question

Express the relationship between the rate of production of oxygen and the rate of disappearance of hydrogen peroxide (H₂O₂) in the following reaction.

\[\ce{2H2O2 -> 2H2O + O2}\]

Answer 1

The given reaction is \[\ce{2H2O2 -> 2H2O + O2}\]

The stoichiometric relationship is 2 moles of H₂O₂ produce 1 mole of O₂

∴ The rate relationship is

\[\ce{\frac{d[O_2]}{dt} = \frac{1}{2} * -\frac{d[H_2O_2]}{dt}}\]

This means the rate of production of oxygen is half the rate of disappearance of hydrogen peroxide.