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Question
Express the following in terms of log 2 and log 3: `"log" root(4)(648)`
Sum
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Solution
`"log" root(4)(648)`
= `"log"(648)^(1/4)`
= `(1)/(4)"log"648`
= `(1)/(4)"log"(2^3 xx 3^4)`
= `(1)/(4)"log"2^3 + (1)/(4)"log"3^4`
= `(3)/(4)"log"2 + (4)/(4)"log3`
= `(3)/(4)"log"2 + "log"3`.
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Expansion of Expressions with the Help of Laws of Logarithm
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