Question

Explain the bond formation if BeCl₂ and MgCl₂.

Answer 1

Bond formation of BeCl₂:

Be = 4;

Electronic configuration of Be atom is = 1s² 2s² 

Bond formation of MgCl₂:

Mg (Z = 12), 1s² 2s² 2p⁶ 3s² it loses two of its valence electron and became Mg²⁺ with inert gas configuration Neon.

The chlorine accepts one electron in its valence shell and because Cl^– ion with Ar electron configuration.

Mg + Cl₂ → Mg²⁺ + 2 Cl^– → MgCl₂

Magnesium cation and two chlorides are attracted by strong electrostatic force to form

MgCl₂ crystals.

Mg = 12,

Electronic configuration: 1s² 2s² 2p⁶ 3s²
Mg⁺²:

Electronic configuration: 1s² 2s² 2p⁶ 3s⁰

Cl = 17, 1s² 2s² 2p⁶ 3s² 3p⁵

Cl^–:

Electronic configuration: 1s² 2s² 2p⁶ 3s² 3p⁶