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Explain how sulphur exists in the +2 oxidation state. - Chemistry (Theory)

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Question

Explain how sulphur exists in the +2 oxidation state.

Explain
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Solution

  1. Sulphur has a valence shell configuration of ns2 np4 with two unpaired electrons in the ground state that allows the formation of +2 oxidation state.
  2. In +2 state, sulphur undergoes sp3 hybridisation, forming a tetrahedral shape with two bonds and two lone pairs.
  3. It can form only two bonds in the ground state, so +2 oxidation state is possible but less stable compared to +4 and +6.
  4. Higher oxidation states (+4, +6) involve excitation of electrons to vacant d-orbitals, but +2 exists in the ground state with two bonds.

Thus, sulphur exists in the +2 oxidation state by using its two unpaired electrons to form two bonds with sp3 hybridisation and two lone pairs on the atom.

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Chapter 7: p-Block Elements - SHORT ANSWER TYPE QUESTIONS [Page 447]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 7 p-Block Elements
SHORT ANSWER TYPE QUESTIONS | Q 39. i. | Page 447
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