English
Tamil Nadu Board of Secondary EducationHSC Science Class 11

Examine the continuity of the following: ex tan x - Mathematics

Advertisements
Advertisements

Question

Examine the continuity of the following:

ex tan x

Sum
Advertisements

Solution

Let f(x) = ex tan x

f(x) is defined at ail points of R.

Expect at `(2"n" + 1) pi/2`, n ∈ Z.

Let x0 be an arbitrary point in `"R" - (2"n" + 1) pi/2`, n ∈ Z

Then `lim_(x -> x_0) f(x) =  lim_(x -> x_0) "e"^x tan x`

= `"e"^(x_0)  tan x_0`  .......(1)

`f(x_0) = "e"^(x_0)  tan x_0`  .......(2)

From equation (1) and (2) we get

`lim_(x -> x_0)  "e"^x  tan x = f(x_0)`

∴ Limit at x = x0 exist and is equal to the value of the function f(x) at x = x0.

Since x0 is arbitrary the limit of the function. f(x) exists at all points in `"R" - (2"n" + 1) pi/2`, n ∈ Z and is equal to the value of the function f(x) at that points.

∴ f(x) satisfies all conditions for continuity.

Hence, f(x) is continuous at all points of `"R" - (2"n" + 1) pi/2`, n ∈ Z

shaalaa.com
Continuity
  Is there an error in this question or solution?
Chapter 9: Differential Calculus - Limits and Continuity - Exercise 9.5 [Page 127]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 9 Differential Calculus - Limits and Continuity
Exercise 9.5 | Q 2. (iii) | Page 127

RELATED QUESTIONS

Examine the continuity of the following:

x + sin x


Examine the continuity of the following:

e2x + x2


Examine the continuity of the following:

`sinx/x^2`


Examine the continuity of the following:

`(x^2 - 16)/(x + 4)`


Find the points of discontinuity of the function f, where `f(x) = {{:(x + 2",",  "if",  x ≥ 2),(x^2",",  "if",  x < 2):}`


Find the points of discontinuity of the function f, where `f(x) = {{:(x^3 - 3",",  "if"  x ≤ 2),(x^2 + 1",",  "if"  x < 2):}`


Find the points of discontinuity of the function f, where `f(x) = {{:(sinx",",  0 ≤ x ≤ pi/4),(cos x",", pi/4 < x < pi/2):}`


At the given point x0 discover whether the given function is continuous or discontinuous citing the reasons for your answer:

x0 = 1, `f(x) = {{:((x^2 - 1)/(x - 1)",", x ≠ 1),(2",", x = 1):}`


Show that the function `{{:((x^3 - 1)/(x - 1)",",  "if"  x ≠ 1),(3",",  "if"  x = 1):}` is continuous om `(- oo, oo)`


For what value of `alpha` is this function `f(x) = {{:((x^4 - 1)/(x - 1)",",  "if"  x ≠ 1),(alpha",",  "if"  x = 1):}` continuous at x = 1?


Let `f(x) = {{:(0",",  "if"  x < 0),(x^2",",  "if"  0 ≤ x ≤ 2),(4",",  "if"  x ≥ 2):}`. Graph the function. Show that f(x) continuous on `(- oo, oo)`


If f and g are continuous functions with f(3) = 5 and `lim_(x -> 3) [2f(x) - g(x)]` = 4, find g(3)


Find the points at which f is discontinuous. At which of these points f is continuous from the right, from the left, or neither? Sketch the graph of f.

`f(x) = {{:((x - 1)^3",",  "if"  x < 0),((x + 1)^3",",  "if"  x ≥ 0):}`


State how continuity is destroyed at x = x0 for the following graphs.


Choose the correct alternative:

Let the function f be defined by `f(x) = {{:(3x, 0 ≤ x ≤ 1),(-3 + 5, 1 < x ≤ 2):}`, then


Choose the correct alternative:

The value of `lim_(x -> "k") x - [x]`, where k is an integer is


Choose the correct alternative:

The function `f(x) = {{:((x^2 - 1)/(x^3 + 1), x ≠ - 1),("P", x = -1):}` is not defined for x = −1. The value of f(−1) so that the function extended by this value is continuous is


Choose the correct alternative:

Let f be a continuous function on [2, 5]. If f takes only rational values for all x and f(3) = 12, then f(4.5) is equal to


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×