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Evaluate using algebraic formula: 993 + 3(99)2 + 3(99) + 1 - Mathematics

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Question

Evaluate using algebraic formula:

993 + 3(99)2 + 3(99) + 1

Evaluate
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Solution

993 + 3(99)2 + 3(99) + 1

This expression matches with,

(a + 1)3 = a3 + 3a2 + 3a + 1   ...[Using (a + b)3 = a3 + 3a2b + 3ab2 + b3]

Here, in the expression b = 1,

Thus, 

(99 + 1)3 = 993 + 3(99)2 + 3(99) + 1

∴ (99 + 1)3 = (100)3

= 100 × 100 × 100

∴ (99 + 1)3 = 1000000

Hence, using an algebraic formula for 993 + 3(99)2 + 3(99) + 1, we get 1000000.

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Chapter 3: Expansions - EXERCISE B [Page 36]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 3 Expansions
EXERCISE B | Q 22. (v) | Page 36
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