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Evaluate the following integral: ∫01x(1-x)5⋅dx - Mathematics and Statistics

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Question

Evaluate the following integral:

`int_0^1 x(1 - x)^5 *dx`

Evaluate
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Solution

Let I = `int_0^1 x(1 - x)^5 *dx`

= `int_0^1 (1 - x)[1 - (1 - x)]^5*dx     ...[because int_0^"a" f(x)*dx = int_0^"a" f("a" - x)*dx]`

= `int_0^1 (1 - x)x^5*dx`

= `int_0^1(x^5 - x^6)*dx`

= `int_0^1 x^5*dx - int_0^1 x^6*dx`

= `[(x^6)/6]_0^1 - [(x^7)/7]_0^1`

= `(1)/(6) (1^6 - 0) - (1)/(7) (1^7 - 0)`

= `(1)/(6) - (1)/(7)`

∴ I = `(1)/(42)`

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Notes

The textbook answer is incorrect. Answer given in the textbook is `1/4^2`. However, as per our calculation, it is `1/42`.

  Is there an error in this question or solution?
Chapter 6: Definite Integration - EXERCISE 6.2 [Page 148]

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