Question

Evaluate:

`tan (sin^-1 - cos^-1(1/2))`

Answer 1

`tan (sin^-1 - cos^-1(1/2))`

`sin^-1 = π/2`

`cos^-1(1/2) = (2π)/3`

So,

`tan (π/2 - (2π)/3)`

`tan (- π/6) = -1/sqrt3`