Question

Evaluate:

`sin (tan^-1 (-sqrt3) - sec^-1 2)`

Answer 1

We know:

`tan^-1 (-sqrt3) = -π/3  "and"  sec^-1 2 = π/3`

So,

`sin (-π/3 - π/3) = sin (- (2π)/3)`

`sin (- (2π)/3) = - sin (2π)/3`

= `-sqrt3/2`