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Evaluate: Cos600 Cos300− Sin600 Sin300

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Question

Evaluate:
cos600 cos300− sin600 sin300

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Solution

On substituting the values of various T-ratios, we get:
cos600 cos300− sin600 sin300

=`(1/2 xx sqrt(3)/2-sqrt(3)/2 xx1/2)=(sqrt(3)/4 - sqrt(3)/4)=0`

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Chapter 11: T-Ratios of Some Particular Angles - Exercises

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 11 T-Ratios of Some Particular Angles
Exercises | Q 2
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