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Question
`int "e"^x [2"cosec" 2x + log(tanx)] "d"x` = ______.
Options
`"e"^x log (tan x) + "c"`
`"e"^x log ("cosec" x) + "c"`
`"e"^x log (sec^2x) + "c"`
`"e"^x log (sec^2x) + "c"`
MCQ
Fill in the Blanks
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Solution
`int "e"^x [2"cosec" 2x + log(tanx)] "d"x` = `"e"^x log (tan x) + "c"`.
Explanation:
`int "e"^x [2"cosec" 2x + log(tanx)] "d"x`
= `"e"^x log (tan x) + "c"` ....`[because int "e"^x ["f"(x) + "f'"(x)]"d"x = "e"^x "f"(x) + "c"]`
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Integrals of Trignometric Functions
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