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Question
`int dx/(sqrt(x + 3) - sqrt(x + 2))` = ______
Options
`2/3log|sqrt(x + 3) - sqrt(x + 2)| + c`
`log|sqrt(x + 3) - sqrt(x + 2)| + c`
`2/3[(x + 3)^{3/2} + (x + 2)^{3/2}] + c`
`(x + 3)^{3/2} + (x + 2)^{2/3} + c`
MCQ
Fill in the Blanks
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Solution
`int dx/(sqrt(x + 3) - sqrt(x + 2))` = `underline(2/3[(x + 3)^{3/2} + (x + 2)^{3/2}] + c)`
Explanation:
Rationalizing the denominator, we get
`int dx/(sqrt(x + 3) - sqrt(x + 2))`
= `int(sqrt(x + 3) + sqrt(x + 2))/((sqrt(x + 3) - sqrt(x + 2))(sqrt(x + 3) + sqrt(x + 2))) dx`
= `int (sqrt(x + 3) + sqrt(x + 2))/((x + 3) - (x + 2)) dx = int(sqrt(x + 3) + sqrt(x + 2))/(x + 3 - x - 2)dx`
= `int {(x + 3)^{1/2} + (x + 2)^{1/2}} dx`
= `(x + 3)^{3/2}/(3/2) + (x + 2)^{3/2}/(3/2) + c`
= `2/3[(x + 3)^{3/2} + (x + 2)^{3/2} + c]`
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Some Special Integrals
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