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Question
During electrolysis of aqueous NaCl, the product obtained at cathode is ____________.
Options
H2(g)
Cl2(g)
H2O(g)
O2(g)
MCQ
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Solution
During electrolysis of aqueous NaCl, the product obtained at cathode is H2(g).
Explanation:
At anode, Oxidation \[\ce{2Cl^-_{( aq)} -> Cl2_{(g)} + 2e^-}\]
At cathode, Reduction \[\ce{2H2O_{(l)} + 2e^- -> H2_{(g)} + 2OH^-_{( aq)}}\]
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\[\ce{2Cl^-_{( aq)} + 2H2O_{(l)} -> Cl2_{(g)} + H2_{(g)} + 2OH^-_{( aq)}}\]
Hence, H2(g) obtained at cathode.
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