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Tamil Nadu Board of Secondary EducationHSC Science Class 11

During an adiabatic process, the pressure of a mixture of monatomic and diatomic gases is found to be proportional to the cube of the temperature. Find the value of γ = CPCV(CPCV)

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Question

During an adiabatic process, the pressure of a mixture of monatomic and diatomic gases is found to be proportional to the cube of the temperature. Find the value of γ = `("C"_"P"/"C"_"V")`

Numerical
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Solution

In an adiabatic process, `"T"^γ"P"^(1 - γ)` = constant

`"P" ∝ "T"^3`

PT−3 = constant .........(1)

`"PT"^(γ/(1 - γ))` = constant ......(2)

`"PT"^(γ/(1 - γ)) = "PT"^-3`

Comparing the powers, `γ/(1 - γ)` = − 3 = − 3 + 3γ

2γ = 3

γ = `3/2`

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Chapter 9: Kinetic Theory of Gases - Evaluation [Page 186]

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Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 9 Kinetic Theory of Gases
Evaluation | Q IV. 6. | Page 186

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