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Question
Draw the graph of the equations x + 2y = 3, 2x + y = 3 and x – y = 0. Show that these three lines pass through the same point. Find the co-ordinates of this common point.
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Solution
1. Solving the equations algebraically
The given equations are:
- x + 2y = 3
- 2x + y = 3
- x – y = 0
Step 1: Solve Equation (3)
From equation (3),
x – y = 0, we get x = y.
Step 2: Substitute x = y into equation (2)
Substituting x = y into 2x + y = 3:
2(y) + y = 3
3y = 3
y = 1
Since x = y, we have x = 1.
Step 3: Verify with equation (1)
Substitute x = 1 and y = 1 into x + 2y = 3:
1 + 2(1) = 3
3 = 3
Since the values satisfy all three equations, the common point of intersection is (1, 1).
To draw the graph, we find at least two points for each line:
For x + 2y = 3:
If x = 1, y = 1; if x = 3, y = 0.
For 2x + y = 3:
If x = 1, y = 1; if x = 0, y = 3.
For x – y = 0:
If x = 0, y = 0; if x = 1, y = 1.

The three lines pass through the same point because the coordinates (1, 1) satisfy all three equations simultaneously. The coordinates of the common point are (1, 1).
