Advertisements
Advertisements
Question
Divide: (32y2 – 8yz) by 2y
Sum
Advertisements
Solution
`(32y^2 - 8yz)/(2y) = (32y^2)/(2y) - (8yz)/(2y)`
= `32/2 y^(2 - 1) - 8/2 y^(1 - 1) z`
= 16y − 4z
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Divide the given polynomial by the given monomial.
8(x3y2z2 + x2y3z2 + x2y2z3) ÷ 4x2y2z2
Divide the given polynomial by the given monomial.
(x3 + 2x2 + 3x) ÷ 2x
Write each of the following polynomials in the standard form. Also, write their degree.
(x3 − 1)(x3 − 4)
Simplify:\[\frac{16 m^3 y^2}{4 m^2 y}\]
Divide 3x3y2 + 2x2y + 15xy by 3xy.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 6y5 + 4y4 + 4y3 + 7y2 + 27y + 6 | 2y3 + 1 |
Using division of polynomials, state whether
3y2 + 5 is a factor of 6y5 + 15y4 + 16y3 + 4y2 + 10y − 35
Divide:
x2 − 5x + 6 by x − 3
Divide:
\[\frac{1}{4} x^2 - \frac{1}{2}x - 12 by \frac{1}{2}x - 4\]
Divide 27y3 by 3y
