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Question
Differentiate the function from over no 15 to 20 sin (x2 + 5)
Options
`cos(x^2 + 5)2x`
`tan x`
`-[sin(sin x)]`
`cos x`
MCQ
Solution
`cos(x^2 + 5)2x`
Explanation:
Let, `y = sin (x^2 + 5)`
Put `x^2 + 5 = t`,
∴ `y = sin t, t -= x^2 + 5`
`(dy)/(dx) = (dy)/(dt) * (dt)/(dx)`
`cos t * (dt)/(dx) = cos (x^2 + 5) d/(dx) (x^2 + 5)`
= `cos (x^2 + 5) xx 2x`
= `2x cos (x^2 + 5)`
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